ln(x^2-1)-ln(2x-1)+ln(2)=0

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Solution for ln(x^2-1)-ln(2x-1)+ln(2)=0 equation: 


Simplifying
ln(x2 + -1) + -1ln(2x + -1) + ln(2) = 0

Reorder the terms:
ln(-1 + x2) + -1ln(2x + -1) + ln(2) = 0
(-1 * ln + x2 * ln) + -1ln(2x + -1) + ln(2) = 0
(-1ln + lnx2) + -1ln(2x + -1) + ln(2) = 0

Reorder the terms:
-1ln + lnx2 + -1ln(-1 + 2x) + ln(2) = 0
-1ln + lnx2 + (-1 * -1ln + 2x * -1ln) + ln(2) = 0
-1ln + lnx2 + (1ln + -2lnx) + ln(2) = 0

Reorder the terms for easier multiplication:
-1ln + lnx2 + 1ln + -2lnx + 2ln = 0

Reorder the terms:
-1ln + 1ln + 2ln + -2lnx + lnx2 = 0

Combine like terms: -1ln + 1ln = 0
0 + 2ln + -2lnx + lnx2 = 0
2ln + -2lnx + lnx2 = 0

Solving
2ln + -2lnx + lnx2 = 0

Solving for variable 'l'.

Move all terms containing l to the left, all other terms to the right.

Factor out the Greatest Common Factor (GCF), 'ln'.
ln(2 + -2x + x2) = 0


Subproblem 1
Set the factor 'ln' equal to zero and attempt to solve:

Simplifying
ln = 0

Solving
ln = 0

Move all terms containing l to the left, all other terms to the right.

Simplifying
ln = 0

The solution to this equation could not be determined.

This subproblem is being ignored because a solution could not be determined.

Subproblem 2
Set the factor '(2 + -2x + x2)' equal to zero and attempt to solve:

Simplifying
2 + -2x + x2 = 0

Solving
2 + -2x + x2 = 0

Move all terms containing l to the left, all other terms to the right.

Add '-2' to each side of the equation.
2 + -2x + -2 + x2 = 0 + -2

Reorder the terms:
2 + -2 + -2x + x2 = 0 + -2

Combine like terms: 2 + -2 = 0
0 + -2x + x2 = 0 + -2
-2x + x2 = 0 + -2

Combine like terms: 0 + -2 = -2
-2x + x2 = -2

Add '2x' to each side of the equation.
-2x + 2x + x2 = -2 + 2x

Combine like terms: -2x + 2x = 0
0 + x2 = -2 + 2x
x2 = -2 + 2x

Add '-1x2' to each side of the equation.
x2 + -1x2 = -2 + 2x + -1x2

Combine like terms: x2 + -1x2 = 0
0 = -2 + 2x + -1x2

Simplifying
0 = -2 + 2x + -1x2

The solution to this equation could not be determined.

This subproblem is being ignored because a solution could not be determined.

The solution to this equation could not be determined.

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